Trắc nghiệm Đạo hàm của các hàm số lượng giác có đáp án (phần 2) !!

A. cosx – x.sinx

B. sinx + x.cosx

C. cosx+ x. sinx

D. cosx + sinx

A.${\sin }^2\left(2x+1\right)\cos \left(2x+1\right).$

B.$12{\sin }^2\left(2x+1\right)\cos \left(2x+1\right).$

C.$3{\sin }^2\left(2x+1\right)\cos \left(2x+1\right).$

D.$6{\sin }^2\left(2x+1\right)\cos \left(2x+1\right).$

A.$\cos \sqrt{2+x^2}.$

B.$\frac{1}{\sqrt{2+x^2}}.\cos \sqrt{2+x^2}.$

C.$\frac{1}{2}.\cos \sqrt{2+x^2}.$

D.$\frac{x}{\sqrt{2+x^2}}.\cos \sqrt{2+x^2}.$

A.$\frac{\cos x+2}{2\sqrt{\sin x+2x}}.$

B.$\frac{\cos x+2}{\sqrt{\sin x+2x}}.$

C.$\frac{2}{2\sqrt{\sin x+2x}}.$

D.$\frac{\cos x}{2\sqrt{\sin x+2x}}.$

A.$2\pi$

B.$\frac{8\pi }{3}$

C.0 

D.$\frac{4\sqrt{3}}{3}$

A.$y\text{'}\left(\frac{\pi }{3}\right)=-1$

B.$y\text{'}\left(\frac{\pi }{3}\right)=1$

C.$y\text{'}\left(\frac{\pi }{3}\right)=-\frac{1}{2}$

D.$y\text{'}\left(\frac{\pi }{3}\right)=\frac{1}{2}$

A.$y\text{'}\left(\frac{\pi }{6}\right)=1$

B.$y\text{'}\left(\frac{\pi }{6}\right)=-1$

C.$y\text{'}\left(\frac{\pi }{6}\right)=\sqrt{3}$

D.$y\text{'}\left(\frac{\pi }{6}\right)=-\sqrt{3}$

A.$-\sqrt{3}$

B. 4

C. -3

D.$\sqrt{3}$

A.$\frac{\sin x+\text{\hspace{0.17em}\hspace{0.17em}}2}{{\left(1+2\sin x\right)}^2}$

B.$\frac{-\sin x-2}{{\left(1+2\sin x\right)}^2}$

C.$\frac{\sin x-2}{{\left(1+2\sin x\right)}^2}$

D.$\frac{-\sin x+2}{{\left(1+2\sin x\right)}^2}$

A.$\frac{\pi \sqrt{3}}{2}\cdot$

B.$\frac{\pi }{2}\cdot$

C.$-\frac{\pi }{2}\cdot$

D.0

A.$\frac{3\sqrt{2}}{2}\cdot$

B.$-\frac{3\sqrt{2}}{2}\cdot$

C. 1

D. 0 

A.$\sqrt{2}$

B. 0

C.$\frac{\sqrt{2}}{2}$

D.1

A.$\frac{4}{3}$

B.$\frac{4}{9}$

C.$\frac{8}{9}$

D.$\frac{8}{3}$

A.$y\text{'}=\frac{1}{{\cos }^{2}2x}$

B.$y\text{'}=\frac{4}{{\sin }^{2}2x}$

C.$y\text{'}=\frac{4}{{\cos }^{2}2x}$

D.$y\text{'}=\frac{1}{{\sin }^{2}2x}$

A.$x=-\frac{\pi }{3}+k2\pi$

B.$x=\frac{\pi }{3}+\frac{k\pi }{2}$

C.$x=-\frac{\pi }{3}+k\pi$

D.$x=-\frac{\pi }{3}+\frac{k\pi }{2}$

A.$\sin \left(\tan x\right)\cdot \frac{1}{{\cos }^{2}x}\cdot$

B.$-\sin \left(\tan x\right)\cdot \frac{1}{{\cos }^{2}x}\cdot$

C.$\sin \left(\tan x\right)$

D.$–\sin \left(\tan x\right)$

A.$y\text{'}=\frac{x\cos x-\sin x}{x^2}$

B.$y\text{'}=\frac{x\cos x+\sin x}{x^2}$

C.$y\text{'}=\frac{x\sin x+\cos x}{x^2}$

D.$y\text{'}=\frac{x\sin x-\cos x}{x^2}$

A.$y^{\text{'}}=\cos x-\sin x+1$

B.$y^{\text{'}}=\cos x+\sin x+\cos 2x$

C.$y^{\text{'}}=\cos x-\sin x+\cos 2x$

D.$y^{\text{'}}=\cos x+\sin x+1$

A.0

B.$\sqrt{2}$

C.$\frac{2}{\pi }$

D.$\frac{2\sqrt{2}}{\pi }$

A.$\sqrt{2}$

B.$\frac{\sqrt{2}}{2}$

C.0

D.$\frac{1}{2}$

A.1

B.$\frac{1}{2}$

C.0

D. Không tồn tại.

A.$y^{\text{'}}\left(\frac{\pi }{6}\right)=1$

B.$y^{\text{'}}\left(\frac{\pi }{6}\right)=-1$

C.$y^{\text{'}}\left(\frac{\pi }{6}\right)=2$

D.$y^{\text{'}}\left(\frac{\pi }{6}\right)=-2$

A.-3

B.$\frac{8}{3}\cdot$

C.$-\frac{8}{9}$

D.$-\frac{8}{3}\cdot$