Cho hai đa thức:
\(P\left( x \right) = - 5{{\rm{x}}^3} - \frac{1}{3} + 8{{\rm{x}}^4} + {x^2};Q\left( x \right) = {x^2} - 5{\rm{x}} - 2{{\rm{x}}^3} + {x^4} - \frac{2}{3}\ \)
Hãy tính P(x)+Q(x) và P(x)-Q(x)
\(\begin{array}{l} P\left( x \right) + Q\left( x \right) = - 5{{\rm{x}}^3} - \frac{1}{3} + 8{{\rm{x}}^4} + {x^2} + {x^2} - 5{\rm{x}} - 2{{\rm{x}}^3} + {x^4} - \frac{2}{3}\\ = 9{{\rm{x}}^4} - 7{{\rm{x}}^3} + 2{x^2} - 5{\rm{x}} - 1 \end{array}\)
\(\begin{array}{l} P\left( x \right) - Q\left( x \right) = - 5{{\rm{x}}^3} - \frac{1}{3} + 8{{\rm{x}}^4} + {x^2} - \left( {{x^2} - 5{\rm{x}} - 2{{\rm{x}}^3} + {x^4} - \frac{2}{3}} \right)\\ = - 5{{\rm{x}}^3} - \frac{1}{3} + 8{{\rm{x}}^4} + {x^2} - {x^2} + 5{\rm{x + }}2{{\rm{x}}^3} - {x^4} + \frac{2}{3}\\ = 7{{\rm{x}}^4} - 3{{\rm{x}}^3} + 5{\rm{x + }}\frac{1}{3} \end{array}\)
-- Mod Toán 7
Copyright © 2021 HOCTAP247