Cho x + y + z khác 0 và x = y + z. Chọn đáp án đúng

A. $\frac{{(xy+yz+zx)}^2-(x^2{y}^2+y^2{z}^2+z^2{x}^2)}{x^2+y^2+x^2}:\frac{{(x+y+z)}^2}{x^2+y^2+z^2}=xy$

B. $\frac{{(xy+yz+zx)}^2-(x^2{y}^2+y^2{z}^2+z^2{x}^2)}{x^2+y^2+x^2}:\frac{{(x+y+z)}^2}{x^2+y^2+z^2}=yz$

C. $\frac{{(xy+yz+zx)}^2-(x^2{y}^2+y^2{z}^2+z^2{x}^2)}{x^2+y^2+x^2}:\frac{{(x+y+z)}^2}{x^2+y^2+z^2}=xyz$

D. $\frac{{(xy+yz+zx)}^2-(x^2{y}^2+y^2{z}^2+z^2{x}^2)}{x^2+y^2+x^2}:\frac{{(x+y+z)}^2}{x^2+y^2+z^2}=1$