Nếu \(\int_{ – 2}^1 {f\left( x \right){\rm{d}}x} = 5\) thì \(\int_{ – 2}^1 {\left[ {f\left( x \right) + 3} \right]{\rm{d}}x} \) bằng

* Hướng dẫn giải

Ta có : \(\int_{ – 2}^1 {\left[ {f\left( x \right) + 3} \right]{\rm{d}}x} = \int_{ – 2}^1 {f\left( x \right){\rm{d}}x} + 3\int_{ – 2}^1 {{\rm{d}}x} = 5 + 3\left. x \right|_{ – 2}^1 = 14\).