Cho \(I=\int\limits_{0}^{2}{f\left( x \right)\text{d}x=3}\). Khi đó \(J=\int\limits_{0}^{2}{\left[ 4f\left( x \right)-3 \right]\text{d}x}\) bằng

* Hướng dẫn giải

\(J = \int\limits_0^2 {\left[ {4f\left( x \right) - 3} \right]{\rm{d}}x}  = 4\int\limits_0^2 {f\left( x \right){\rm{d}}x}  - 3\int\limits_0^2 {{\rm{d}}x}  = 4.3 - \left. {3x} \right|_0^2 = 6\)