(log2(24) - 1/2(log2(72))/(log3(18)-1/3(log3(72))

* Hướng dẫn giải

$\frac{{\log }_{2}24-{\log }_2\sqrt{72}}{{\log }_{3}18-{\log }_3\sqrt[3]{72}}=\frac{{\log }_2{2}^{{\displaystyle \frac{3}{2}}}}{{\log }_3{3}^{{\displaystyle \frac{4}{3}}}}=\frac{9}{8}$